sed replace single quote with two single quotes, As noted in the comments to the question, it's not really about sed, but how to include a quote in a quoted string in a shell (e.g. How to escape single quotes in sed for multi line pattern. ex. You can effectively have a single quote between single quotes by writing '\'' (close single quote, one literal single quote, open single quote). In the shell, everything between single quotes is interpreted literally, except for single quotes themselves. To clarify a previous answer, you need to escape the quote with a backslash, but you can't do that within a single-quoted expression. Sed uses basic regular expressions. As * signify that consider 'all data' after the sign. You can quote anything with the backslash. escape single quote in sed Programming. Because I am using json I need to wrap the --extra-vars with single quotes as the json requires the double quotes. Thus the result is supposed to be: The simplest thing to do is to use different quotes around your sed command: "5i'mytext' 16/16" Normally it's best to use single quotes around a sed command but it would be more tricky in this case: '5i'"'"'mytext'"'"' 16/16' You can't escape a single quote within a string quoted with single quotes. i m trying the following command but its not working: sed 's/find/\'replace\'/g' myFile but the sed enters into new line [root@asamiLinux root]# sed 's/find/re\'place/g' myFile > I havn't any idea how to put single quote in my replace string. In other … Remember, the backslash is the strongest of all quoting mechanisms. So you have to close the quote, add an escaped quote, then open the quotes again. Let me rephrase that. But then I can't get single quotes to work inside a json variables. I need not have escape charachters before each. ... How to escape a single quote inside a double quote string in bash script? The command that worked is below. The reason single quotes works is because this tells the shell that the enclosed string is to be passed to sed as is without the shell consuming the leading backslash(s). sed "s/= '\*'/= '^'/g" filename.sh i used double quote to start the search, so thus I dont need to add '\' to the single quotes. Thanx @DummyHead Here's another approach: if you use single quotes, the sed command is exactly as you type it. I have some code written in VHDL that looks as follows: Code: foo = "bar"; foo <= 'bar', foo : bar. 3. sed from terminal when replacing double quotes with single quotes. If you want to include a single quote in an argument that starts with a single quote, you must turn off the mechanism started by the single quote, and use a different quoting method. The single quotes that you're trying to use in your insertion string are interfering with the ones around the sed command. Escaping Single-Quotes in sed This is a just a re-post of this excellent article by Stuart Coleville: Using single quotes in BASH ensures that the shell doesn’t expand the contents of the quoted string and this is useful most of the time. Your early help woud be appreciated. 1. sed … The pattern "foo = "bar";\n foo <= 'bar'," needs to be replaced (but no other patterns in this file). That is: 'foo'\''bar', which breaks down as: 'foo' quoted foo \' escaped ' 'bar' quoted bar; yielding foo'bar. I just need it before '*'. Recognize that the command is being passed from the shell to sed, & each consumes a leading backslash as an "escape" if given the chance. bash). Ones around the sed command is exactly as you type it * signify that consider data. In other … How to escape a single quote within a string quoted with single quotes with! Sed from terminal when replacing double quotes quoting mechanisms quotes as the json the! 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